8x^2+56x=-48

Solution for 8x^2+56x=-48 equation:

8x^2+56x=-48

We move all terms to the left:

8x^2+56x-(-48)=0

We add all the numbers together, and all the variables

8x^2+56x+48=0

a = 8; b = 56; c = +48;
Δ = b2-4ac
Δ = 562-4·8·48
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-40}{2*8}=\frac{-96}{16}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+40}{2*8}=\frac{-16}{16}
=-1
$